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2023 AP Physics 1 Mechanics Mock

1:30:00

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Total Marks: 50

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ADVANCED PLACEMENT (COLLEGE BOARD)AP-P1-23-MCQ• Official Candidate Question Paper

2023 AP Physics 1 Mechanics Mock • AP Physics 1: Algebra-Based

base

[1 Marks]

Torque and Rotational Equilibrium

Worth 1 Marks • Medium Level

A uniform meter stick of mass

M

is pivoted at its centre of mass (

x = 0.50\text{ m}

). A

200\text{ g}

mass is placed at the

x = 0.20\text{ m}

mark. At what position must a

300\text{ g}

mass be placed to maintain rotational equilibrium

\sum \tau = 0

Formula Guide:

Torque equilibrium:

\tau_{\text{left}} = \tau_{\text{right}} \implies m_1 g d_1 = m_2 g d_2

. Distance from pivot:

d_1 = 0.50 - 0.20 = 0.30\text{ m}

. Thus

(0.200)(0.30) = (0.300)(d_2) \implies d_2 = 0.20\text{ m}

to the right of pivot. Ruler coordinate:

0.50 + 0.20 = 0.70\text{ m}

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